How to calculate electrical energy consumption


How can I find out how many kilowatt-hours a device consumes based on its declared power?

After reading this post, you can find out how much energy (Wh, kW/h) the device consumes, based on its declared power (W, kW), and also how much you need to pay for energy when using this device.

Example 1: Let's say you have a kettle with a power of 2100 W. And you need to find out how much to pay for energy using a kettle. It consumes 2100 W per hour. That is, 2.1 kW is the same as 2.1 kW/h. As you know, it takes 5 minutes to boil. Therefore, we divide 2100 W by 60 to find out how many watts are spent per minute. 2100 / 60 = 35 watts per minute. To find out how much energy is spent in 5 minutes, we must multiply 35 by 5. 35 * 5 = 175 watts in 5 minutes. We will boil 5 times a day, so we will multiply by 5 more. 175 * 5 = 875 watts for 5 boils. As you know, you need to pay once a month. Therefore, we multiply 875 watts by 30 days. 875 * 30 = 26250 watts = 26.25 kilowatts per month. Let's round up 27 kilowatts per month. So, the price for 1 kilowatt is 4 rubles 68 kopecks. Therefore, let's multiply 27 by 5. We don't take any pennies into account. 27 * 5 = 135 rubles. Result: the payment for electricity will be 135 rubles.

Another example: an energy-saving 7 W LED lamp. It consumes these 7 W per hour. It will burn for 5 hours a day. 7 * 5 = 35 W for 5 hours of burning Next, multiply 35 by 30 days. 35 * 5 = 1050 W per month = 1.05 kW per month 1.05 multiplied by 5. 1.05 * 5 = 5 rubles. Result: fee - 5 rubles.

And the last example: a 7 kW electric stove. It consumes this 7 kW per hour. We will cook on it for 3 hours a day. 7000 W * 3 = 21000 W = 21 kW for 3 hours of cooking 21000 W multiplied by 30 days. 21000 * 30 = 630000 W = 630 kW per month. And multiply 630 by 5 rubles 630 * 5 = 3150 rubles. The energy fee will be 3150 rubles. Therefore, whoever has an electric stove at home has an electricity tariff where 1 kW costs less. That is, not 5 but 3 rubles. 630 * 3 = 1890 rubles fee with tariff for electric stoves.

Source

How to take meter readings correctly?

The meter display shows data on the electricity used for the entire time.

Write down these numbers, down to the decimal point. All that comes after it are decimal parts, which change quickly and do not need to be taken into account.

The values ​​of the previous period must be subtracted from the recorded reading. Thus, you get the electricity consumption for a real period of time in kilowatts per hour.

Now you need to multiply the resulting number by the index, which is the tariff for 1 kW/h (this coefficient can be found in previous receipts or checked with the company that provides electricity to your home). The resulting figure is your next payment for electricity.

Day-night meters are capable of correctly counting electricity consumption separately for daytime and nighttime. According to the instructions described earlier, calculate two values ​​- electricity consumption over the past period at night and during the day. Multiply each resulting value by the corresponding index and add these numbers.

Calculation of electricity consumption by household appliances

Calculating the electricity consumption of energy-receiving devices installed or planned to be installed in your home can be useful if you are planning to upgrade your home electrical network (lay a new cable, install a new protection device, etc.) or are not sure that the old electrical wiring will withstand new electrical appliances.
In addition, the calculation in question is able to assess the accuracy of the electrical energy meter readings and even help plan your expenses in the area of ​​utility consumption.

How to calculate electricity consumption knowing the power

Whatever the goals of the calculation of electricity consumption, it is carried out according to the rated power of the energy receivers. In other words, at the first stage of the calculation, you need to collect data on the technical characteristics of all the devices you use - from a light bulb on the ceiling to a washing machine.

Important . Information about the power consumption of an electrical appliance is usually available on its nameplate (this is a metal plate or sticker on its back wall or on the bottom), as well as in the technical documentation for this power receiving device. If you do not have access to the necessary information, you can find it on the Internet by entering the name of the electrical appliance into the search engine.

In addition, you can use the table of power of electrical appliances, which will be given below. The data in this table are averaged for all devices for a particular purpose. Your electrical equipment may have a power that differs from the tabular data.

Rated power, W

Energy-receiving household devices

Rated power, W

Warm floor (per 1 sq. m)

Lighting (per 1 sq. m)

So, in order to determine the electrical energy consumption of household electrical appliances, it is necessary to know the power consumed by each of them, as well as the operating time of each of them. In this case, the formula for calculating electricity consumption by power of one power receiving device will look like this:

where P is the rated power of this device, kW; T is its operating time, hours.

Connected home appliances

Simultaneously connected household appliances

If you want to calculate the power consumption in a section of the electrical network to which a number of devices are connected, or all power consumption in a house or apartment, you should sum up the power consumption of all devices included in this circuit. That is, the calculation formula in this case will take the following form:

Formulas for direct electric current

A direct electric current does not change in magnitude or direction. It is used to calculate a closed, homogeneous circuit, power and other parameters. Therefore, it is important to know the formulas for it and the basic laws associated with it.

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Basic list of formulas

Ohm's law for a section of a homogeneous chain

For electric current to exist, a field is needed. For its formation, potentials or their difference, expressed by voltage, are needed. The current will be directed towards reducing the potentials, and the electrons will begin to move in the opposite direction. In 1826, G. Ohm conducted a study and concluded: the higher the voltage, the greater the current that passes through the section.

For your information! Adjacent conductors conduct electricity differently. That is, each element has its own conductivity, electrical resistance.

As a result, according to Ohm’s theorem, the current strength for a section of a homogeneous circuit will be directly proportional to the voltage across it and inversely proportional to the conductive resistance.


Ohm's law

Using the formula I = U / R, where I is considered to be the current strength, U is the voltage, and R is the electrical resistance, the latter value can be found if p * l / S, where p is the conductor resistivity, l is the length of the conductor, and S — cross-sectional area of ​​the conductor.

Ohm's law for a closed circuit with a current source

Ohm made a formula for a closed circuit. According to it, the current in this section from a current source having internal and external load resistance is equal to dividing the electromotive force of the source by the sum of the internal and external resistance. It looks like this: I = e / R + r, where I is the current force, e is the emf, R is the resistance, and r is the internal resistance of the voltage source.

Note! In the physical sense, according to this law, the higher the EMF, the higher the source of energy, the greater the speed of movement of charges. The higher the resistance, the lower the current.


Ohm's law for a closed circuit

DC operation

Energy, when passed through a conductor, moves in an orderly manner into the carrier. While moving, it does work. As a result, direct current work is the field activity aimed at transferring electrical charges along a conductor. It is equal to I multiplied by the voltage and time performed by the work.

Joule-Lenz law

When electricity passes through any resistive conductor, heat is always released. The amount of heat released over a certain period of time is determined by the Joule-Lenz law. According to the formula, the heat power is equal to the electricity density multiplied by the voltage - w =j * E = oE(2).

Note! In practical terms, the law is important for reducing electricity loss, selecting a conductor for an electrical circuit, selecting an electric heating device and using a fuse to protect the network.


Joule-Lenz law

Apparent power developed by the current source

Power is work done in one second of time. Electrical power is a physical quantity that characterizes the speed of transmission with the conversion of electricity.

The work that is developed by the source of electricity throughout the circuit is total power. It can be determined by the formula P = El, where E is considered the emf, and I is the value of the current characteristic.

For your information! If there is a linear load, then the total power indicator is equal to the square root of the squares of the active and reactive work of the source. If there is a nonlinear load, then it is equal to the square root of the squares of the active and inactive work of the source.


Full power

In practical measurements, such work is expressed in kilowatts per hour. Used to measure electricity consumption in domestic and industrial environments, to determine the generated electrical energy in electrical equipment.

Net power

The maximum or useful power is that which is released in the external gap of the circuit, that is, during the load of the resistor. It can be used to perform any tasks. A similar concept can be applied to calculate how an electric motor or transformer works, which is capable of consuming active and reactive components.

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Net power

The useful power indicator can be calculated using three formulas: P = I 2R, P = U2 / r, P = IU, where I is the current strength in a certain section of the circuit; U is the voltage on part of the terminals (clamps) of the current source, and R is the load resistance or external circuit.

Current source efficiency

The efficiency of a current source is the division of the useful power indicator by the total. If the internal resistance of the source is equal to the external resistance, then half the results of all the work will be lost in the source, and the other half will be allocated to the load. In such a situation, the efficiency will be 50%.

If we consider this concept most fully, then when electric charges move along a closed electrical circuit, the current source performs a certain useful and complete work. By performing the first, it moves charges into the external circuit. Doing the second work, charged particles move throughout the area.


Current source efficiency

Note! A useful effect is achieved when the resistance of the external electrical circuit has a certain value, depending on the source and load. The ratio of useful work to full is expressed by the formula: η = Apolez / Apoln = Ppolez / Pfull = U/ε = R / (R + r).

Kirchhoff's first rule

According to Kirchhoff's first law, the current sum in any part of the electrical circuit is equal to zero. The directional charge towards the node is positive, and from it - negative. The algebraic current sum of charges that are directed towards a node is equal to the sum of those that are directed away from it. If we translate this rule, we can get the following definition: as much current enters the node, so much comes out of it. This rule follows from the law on the conservation of charged particles.

By solving linear equations based on Kirchhoff's rules, it is possible to find all current values ​​and voltages in areas of direct, alternating and quasi-stationary electric currents.

Note! In electrical engineering, Kirchhoff's rule is of particular importance, since it is universal for solving many problems in the theory of electrical circuits. It can be used to calculate complex electrical circuits. Using it, you can obtain a system of linear equations for currents or voltages on all internodal branches of the circuits.


Kirchhoff's first rule

Kirchhoff's second rule

The second Kirchhoff rule follows from the first and third Maxwellian equations. According to it, the algebraic sum of the voltages on the resistive elements of a closed section is equal to the sum of the emf that is included in it. If there is no EMF in the area, then the total voltage drop is equal to zero. To put it even more simply, during a complete bypass of the circuit, the potential changes. It returns to its original value.

A common case for a section of one circuit is Ohm's law. When composing stress equations for a circuit, it is necessary to select its positive bypass. To do this, you need to know that when selecting a bypass, the branch voltage drop indicator will be positive if the bypass direction in the branch coincides with the one that was previously selected. If it does not match, then the branch voltage indicator will be negative.

Important! Kirchhoff's second rule can be used in a linear or nonlinear linearized circuit for any change in currents and voltages.


Kirchhoff's second rule

As a result, in order to understand the basics of physics, electrical phenomena, electrodynamics and successfully use knowledge in the process of life, you need to know the derived theorems, laws, formulas and rules in the field of electricity, which are presented above. For example, by imagining what this or that formula looks like, you can solve any problem in a textbook on physics or life.

Application of energy consumption calculations in practice

Let's look at examples of how you can calculate the kilowatts consumed over a certain period of time by one or another energy receiver(s).

Example 1. Calculate the monthly power consumption of a professional hair dryer for personal daily use.

Hair dryers used by professional hairdressers have impressive power. Let's say the rated power of our device is 2000 W. At the same time, one person uses it and spends about 10 minutes a day drying and styling their hair with it. Since the task does not contain specific information about how long the billing month lasts, we use the average number of days - 30.4. Thus, we have the following solution to the problem under consideration:

Example 2. Calculate the annual power consumption in a room in which the following items of electrical equipment are located and periodically used: TV, air conditioner, laptop.

At the same time, the owner of the room watches TV only in the morning, getting ready for work, and in the evening during dinner - a total of 1.5 hours a day. He works on his laptop in the evenings - about 2 hours a day. The air conditioner is used exclusively for cooling the air in the summer, and only 3 weeks in total are hot enough for this.

Methods for calculating electricity consumption of household appliances

Content

  1. How to determine electricity consumption
  2. According to the table
  3. According to the formula
  4. Online calculator
  5. How to calculate electricity by power

Every year the cost of electrical energy becomes more and more, and this in turn forces users to think about controlling its consumption and saving. The consumption rate and cost of electricity differs depending on the purpose of the household, territorial and climatic features, availability of energy resources and other factors. Knowing the price and the number of kilowatt-hours generated, you can understand the final amount the user will pay. If the price per kWh is a fixed value, then consumption is a calculated value.

Basic formulas of electricity

Studying the fundamentals of electrodynamics and electrics is impossible without determining the electric field, precise charges, resistance and other phenomena.


Electricity formulas

Therefore, it is important to consider all the basic formulas of electricity and examples of solving problems using them.

Coulomb's law

According to a short description, this is a physical law that talks about the interaction between directly standing point electric charges, depending on the distance at which they are located. According to the full definition, the formulation means that a vacuum is formed between two points in the form of electric charges. A specific force appears there, which is proportional to the multiplication of their modular particles divided by the square of the distance.

Distance is the length that connects charges. The interaction force is directed along the segment. Coulomb force is a force that is repulsive for charges minus-minus and plus-plus and attractive for charges minus-plus and plus-minus.

Note! The electric force formula looks like this: F=k⋅|q1|⋅|q2|/r2, where F is the force of the charge, q is the magnitude of the charge, r is the vector or distance between charges, and k is the proportionality coefficient. The latter is equal to c2·10−7 H/m.


Coulomb's law

Solving the problem with Coulomb's law. If you have charged balls that are located at a distance of 15 cm and repel with a force of 1 N in search of the initial charge, you can identify the unknown by converting the base units to the SI system and substituting the values ​​​​into the indicated formula. The value will be 2 * 5 * 10 (-8) = 10 (-7).

Field strength of a solitary point charge

The electric field, being matter created by electric point charges, is characterized by different quantities, including intensity. Tension acts as a vector quantity or force characteristic of the field, which is directed towards the electrostatic interaction of charges. To obtain it, you need to use the formula E = k (q / r (2)), where E is a vector field.


Field strength of a solitary point charge

According to this formulation, the charge field strength is inversely proportional to the square value of the distance from the charge. That is, if the gap increases several times, the voltage indicator decreases by four.

You can apply the law to solve problems. For example, the radius is unknown. Then you need to convert the constant. You need to solve the equation E / r (2) = kq by substituting known numbers.

Potential of a point in the field of a point charge

Potential in an electrostatic field is a scalar quantity that is equal to dividing the potential charge energy indicator by it. It does not depend on the value of q that is placed in the region. Since the potential energy indicator depends on which coordinate system is chosen, the potential is determined accurate to a constant. It is equal to the work field that displaces a unit positive charge to infinity. Expressed through φ = W / q =const.

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Potential of a point in the field of a point charge

Note! In tasks, you can convert a constant. If W is unknown, then we can divide q by φ, and if q, then W by φ.

Potential charge energy in an electrostatic field


Potential energy of a charge in an electrostatic field
Since the work of an electric field does not depend on the chosen motion of the charged particle, but on its initial and final position, there is the term potential energy. This is a scalar quantity in a space coordinate that shows how the force works when a particle moves along an arbitrary interval from one point to another. It is equal to the difference in the values ​​of particle movement in this interval. It is expressed in the following form: A = P1 - P2, where P1 can be x, y and z, and P2 can be x2, y2 and z2. In physics problems, you need to draw a graph, substitute known values ​​into a constant, and solve equations.

Potential energy of charge q1 in the field of a point charge

When charged particles move across a field from one point to another, they perform some work over a certain time period. The potential energy at these points does not depend on which path the charged particles take. The energy of the first charge is proportional to its modulus. This is all expressed in the formula presented in the picture below. Problems can be solved by using the presented constant and inserting known values.


Potential energy of charge q1 in the field of a point charge

Gauss's theorem

The fundamental law in electrodynamics, included in Maxwell's equations. This is a consequence of the Coulomb inference and the principle of superposition. Along it, the field voltage vector moves through an arbitrary value of a closed surface surrounded by charges. It is proportional to the sum of charged particles that are inside this closed space. The specified vector is divided by e0. All this is expressed by the formula below.


Gauss's theorem

Electric field strength near the surface of the conductor

The intensity of the total space of charged particles is directly proportional to the surface indicator of their density. If the problem requires finding the tension, and the surface charged density is sigma, then you need to draw a cylinder and designate that the flux through its side surface is 0. In this case, the tension lines will be parallel to the side surface. It turns out that φ = 2φ, main = 2еs, and 2es = q / 2ε0.


Electric field strength near the surface of the conductor

Capacitance of parallel plate capacitor

Capacitance is a conductive characteristic through which an electric charge can accumulate energy. A flat capacitor is a series of oppositely charged plates separated by a thin dielectric layer. The capacitance of a flat capacitor is considered to be its characteristic, its ability to accumulate electrical energy.

Note! This is a physical quantity that is equal to the charge divided by the potential difference of its plate. The charge in this case is one charged plate.

If the problem requires finding out the capacitance of a capacitor made of two plates with an area of ​​10(-2) square meters and there is a 2*10(-3) meter sheet in them, ε0 is the electric constant with 8.85×10-12 farads per meter and ε =6 is the dielectric constant of mica. In this case, you need to insert the values ​​into the formula C= ε* ε* S/d.


Capacitance of parallel plate capacitor

Energy of a parallel plate capacitor

Since any particle of a capacitor has the ability to store energy, which is stored on the capacitor plate, calculating this very E is simple, since in order for the element to charge, it needs to do work. The work is done by the field. As a result, the following formula was derived: Ep = A = qEd, where A is the work, d is the distance.


Energy

According to the table

A simplified version of the calculation is an approximate calculation using this table or adapting it to your situation.

Name of electrical deviceMaximum power, kWNumber of devices, pcs.Operating time per day, hMonthly consumption (30 days), kWAmount to be paid, rub. (tariff 3.48)
Fridge0,61236125,28
TV0,52575261
Washing machine2,213198689,04
Dishwasher2,513225783
Kettle1,21136125,28
Microwave1,110,516,557,42
Lighting (lamp)0,011051,55,22

This table shows the daily operation of electrical appliances at maximum power; in reality, consumption may differ. Some appliances may run for several hours per week or month, so it is best to base your estimate on the actual situation on site.

The tabular form allows you to clearly understand which device consumes the most energy, analyze the possibility of reducing the operation of certain devices, switch to more energy-efficient devices, or refuse to use some devices.

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